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Sagot :
Given the numbers:
[tex]3^{\frac{1}{3}},\text{ }4^{\frac{1}{2}},\text{ }\sqrt[3]{9},\text{ 1}^8,\text{ \lparen-}\frac{1}{2})^{-2}[/tex]Let's arrange the numbers from the least to the greatest without the use of a calculator.
Now, let's first simplify each term.
We have:
[tex]\begin{gathered} 3^{\frac{1}{3}}=\sqrt[3]{3} \\ \\ 4^{\frac{1}{2}}=\sqrt{4}=2 \\ \\ \sqrt[3]{9} \\ \\ 1^8=1 \\ \\ -(\frac{1}{2})^{-2}=(-2)^2=4 \end{gathered}[/tex]Therefore, arranging the numbers from the least to the greatest, we have:
[tex]\begin{gathered} 1 \\ \\ \\ 3^{\frac{1}{3}} \\ \\ \\ 4^{\frac{1}{2}} \\ \\ \sqrt[3]{9} \\ \\ \\ (-\frac{1}{2})^{-2} \end{gathered}[/tex]
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