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how much money should be deposited today in the account that are 7%, compounded and semi-annually so they will accumulate to 11,000 in 3 years

How Much Money Should Be Deposited Today In The Account That Are 7 Compounded And Semiannually So They Will Accumulate To 11000 In 3 Years class=

Sagot :

The rule of the compound interest is

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

A is the new amount

P is the initial amount

r is the rate in decimal

n is the number of the periods per year

t is the number of years

Since the rate is 7% compounded semi-annual, then

r = 7/100 = 0.07

n = 2

Since the amount after 3 years will be $11 000, then

A = 11 000

t = 3

Substitute them in the rule above to find P

[tex]\begin{gathered} 11000=p(1+\frac{0.07}{2})^{2(3)} \\ 11000=p(1.035)^6 \end{gathered}[/tex]

Divide both sides by (1.035)^6 to find P

[tex]\begin{gathered} \frac{11000}{(1.035)^6}=P \\ 8948.507087=P \end{gathered}[/tex]

Round it to the nearest cent (2 decimal places)

P = $8948.51

The amount invested was $8948.51