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Sagot :
Solve the system of equations:
4x-2y=10 (1)
y=2x-5 (2)
We can substitute 2 in 1:
4x-2(2x-5)=10
4x-4x+10=10
0=0
Since the solution of the system of equation is 0=0 we can say that it has infinite solutions.
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