SOLUTION:
Step 1:
In this question, we are given the following:
Step 2:
The details of the solution are as follows:
[tex]Length\text{ of Arc =}\frac{\theta}{360^0}\text{ x 2}\pi\text{ r}[/tex][tex]\begin{gathered} where\text{ }\theta\text{ = 137}^0 \\ radius\text{ = 25 inches} \end{gathered}[/tex][tex]Length\text{ of arc = }\frac{137^0}{360^0}\text{ x 2 x }\pi\text{ x 25}[/tex][tex]Length\text{ of arc =}\frac{137^0}{360^0}\text{ x }\frac{50\pi}{1}[/tex][tex]Length\text{ of Arc = }\frac{21,519.90968}{360}[/tex][tex]Length\text{ of Arc = 59.77752688 inches}[/tex][tex]Length\text{ of Arc }\approx\text{ 59. 8 inches \lparen to the nearest tenth \rparen}[/tex]
