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[OH﹘] = 6.5 x 10-5Mfind the pH and pOH

Sagot :

Answer:

pH = 9.81

pOH = 4.19

Explanations:

The formula for calculating the pOH of a solution is given as:

[tex]pOH=-log[OH^-][/tex]

Given the following parameters

[tex][OH^-]=6.5\times10^{-5}M[/tex]

Substitute

[tex]\begin{gathered} pOH=-log(6.5\times10^{-5}) \\ pOH=-(-4.19) \\ pOH=4.19 \end{gathered}[/tex]

Determine the pH of the solution

[tex]\begin{gathered} pH+pOH=14 \\ pH=14-pOH \\ pH=14-4.19 \\ pH=9.81 \end{gathered}[/tex]

Therefore the pH and pOH are 9.81 and 4.19 respectively