Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Fill in the blanks (B1, B2, B3) in the equation based on the graph.(a-B1)2 + (y-B2)² = (B3)²8182=83=Blank 1:

Fill In The Blanks B1 B2 B3 In The Equation Based On The GraphaB12 YB2 B3818283Blank 1 class=

Sagot :

Given: a circle is given with center (3,-3) and equation

[tex](x-B_1)^2+(y-B_2)^2=(B_3)^2[/tex]

Find:

[tex]B_{1,\text{ }}B_{2,}B_3[/tex]

Explanation: the general equation of the circle with center (a,b) and radius r is

[tex](x-a)^2+(y-b)^2=r^2[/tex]

in the given figure the center of the circle is at (3,-3)

so the equatio of the circle becomes

[tex](x-3)^2+(y+3)^2=(3)^2[/tex]

on comparing eith the given equation we get

[tex]B_1=3,\text{ B}_2=-3\text{ and B}_3=3[/tex]

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.