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we have to write the equation of the line using y=mx+b passing through the points (6,2) and (2,4)

Sagot :

The general equation of line passes through point (x_1,y_1) and (x_2,y_2) is,

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

Determine the equation of line passes through point (6,2) and (2,4).

[tex]\begin{gathered} y-2=\frac{4-2}{2-6}(x-6) \\ y-2=\frac{2}{-4}(x-6) \\ y=-\frac{1}{2}x+3+2 \\ =-\frac{1}{2}x+5 \end{gathered}[/tex]

So equation of line is y = -1/2x + 5.

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