Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Answer:
0.1M sugar < 0.1 M NaCl < 0.08M CaCl2 < 0.04 M Na2SO4
Explanations:
First we must understand that the higher thecnoncentration of a compound, the lower the melting point. This shows that 0.04 m Na2SO4 will have highest melting point followed by 0.08 M CaCl2
Since 0.1M of sBgar and 0.1M of NaCl have the same molarity, we will determine the effect of solute and ionic bonding between compound on melting point. Since common salt (NaCl) is made up of stronger ionic bonds, it will have higher melting point than sugar.
The increasing order of their melting point wile be 0.1M sugar < 0.1 M NaCl < 0.08M CaCl2 < 0.04 M Na2SO4
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.