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an unusually shaped section of a park is to be paved. this section is drawn to scale below. the length of a single grid segment is 1 m.

An Unusually Shaped Section Of A Park Is To Be Paved This Section Is Drawn To Scale Below The Length Of A Single Grid Segment Is 1 M class=

Sagot :

Since the length of a single grid square is 1m, then its area is:

[tex]A=1m\times1m=1m^2\text{.}[/tex]

Now, to compute the area of the given section we will use the following diagram.

To compute the area of each triangle we will use the following formula for the area of a triangle:

[tex]\begin{gathered} A=\frac{bh}{2}, \\ \text{where b is the base of the triangle and h is its height.} \end{gathered}[/tex]

And to compute the area of the rectangle we will use the following formula:

[tex]\begin{gathered} A=bh, \\ \text{where b is the base of the rectangle and h is its height.} \end{gathered}[/tex]

Therefore the area of triangle A is:

[tex]A_A=\frac{6m\cdot2m}{2}=6m^2\text{.}[/tex]

The area of triangle B is:

[tex]A_B=\frac{4m\cdot2m}{2}=4m^2\text{.}[/tex]

The area of triangle C is:

[tex]A_C=\frac{3m\cdot1m}{2}=1.5m^2\text{.}[/tex]

The area of triangle D is:

[tex]A_D=\frac{5m\cdot1m}{2}=2.5m^2\text{.}[/tex]

The area of rectangle E is:

[tex]A_E=12m^2\text{.}[/tex]

Finally, the area of the given section is:

[tex]\begin{gathered} A=A_A+A_B+A_C+A_D+A_E \\ =6m^2+4m^2+1.5m^2+2.5m^2+12m^2=26m^2\text{.} \end{gathered}[/tex]

Answer:

The area of a single grid square is:

[tex]1m^2\text{.}[/tex]

The approximate area of the section that will be paved is:

[tex]26m^2\text{.}[/tex]

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