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In ΔHIJ, the measure of ∠J=90°, the measure of ∠I=62°, and IJ = 86 feet. Find the length of HI to the nearest tenth of a foot.

Sagot :

To get the angle at H:

The total angle in a triangle = 180

< H = 180 - (90+ 62)

To get the length HI, the hypotenuse

[tex]\cos \text{ 62 = }\frac{86}{x}[/tex]

[tex]\begin{gathered} x\text{ = }\frac{86}{\cos \text{ 62}} \\ \\ x\text{ = }\frac{86}{0.4695} \\ x\text{ = 183.185 f}eet \end{gathered}[/tex]

The length HI = x = 183. 2 Feet to the nearest tenth

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