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From a point x = 80 feet in front of a public library, the angles of elevation to the base of the flagpole and the top of the flagpole are = 29.5° and 39° 45', respectively. The flagpole is mounted on the front of the library's roof. Find the height of the flagpole.

Sagot :

Let's draw the scenario to better understand the details.

To be able to determine the height of the flagpole, let's create two different triangles with 29.5° and 39° 45' angle. The two triangles have one common base at 80 Feet, yet have different heights at H+h and H respectively.

Where,

H = Height of the library

h = Height of the flag

The two triangles are proportional at a common base, thus, let's generate this expression using the Law of Sines:

[tex]\frac{H+h}{\sin(39\degree45^{\prime})}\text{ = }\frac{H}{\sin(29.5^{\circ})}[/tex]

Let's simplify,

[tex]\frac{H+h}{\sin(39\degree45^{\prime})}\text{ = }\frac{H}{\sin(29.5^{\circ})}\text{ }\rightarrow\text{ (}H+h)(\sin (29.5^{\circ}))\text{ = (H)(}\sin (39\degree45^{\prime}))[/tex][tex]H\sin (29.5^{\circ})\text{ + h}\sin (29.5^{\circ})\text{ = H}\sin (39\degree45^{\prime})\text{ ; but }29.5^{\circ}=29^{\circ}30^{\prime}[/tex][tex]H\sin (29^{\circ}30^{\prime})\text{ + h}\sin (29^{\circ}30^{\prime})\text{ = H}\sin (39\degree45^{\prime})[/tex][tex]\text{h}\sin (29^{\circ}30^{\prime})\text{ = H}\sin (39\degree45^{\prime})\text{ - }H\sin (29^{\circ}30^{\prime})[/tex][tex]\text{ h(}0.4924235601)\text{ = H(0.63943900198) -H}(0.4924235601)[/tex][tex]\text{ h(}0.4924235601)\text{ = H(0.14701544188)}[/tex][tex]undefined[/tex]

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