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Sagot :
a) From the graph, we see that the function takes the value y = 4 when x = 4, so we have:
[tex]\lim _{x\rightarrow4}f(x)=4.[/tex]b) We see that the curve tends to -∞ when x approaches zero from the left, so we have:
[tex]\lim _{x\rightarrow0^-}f(x)=-\infty.[/tex]c) We see that curve increases without limit when x tends to infinity, so we have:
[tex]\lim _{x\rightarrow\infty}f(x)=\infty.[/tex]d) From the graph, we see that the function tends to y = 0 when x approaches zero from the right, so we have:
[tex]\lim _{x\rightarrow0^+}f(x)=0.[/tex]e) Yes, there are two possible values of x for the limit of the function approaching 4:
• x = 2,
,• x = 4.
By definition, a function is continuous when its graph is a single unbroken curve.
We see that at the points x = 2 and x = 4 the curve is a single unbroken curve, so we conclude that the function is continuous at those points.
Answers
a, b, c, d
[tex]\begin{gathered} \lim _{x\rightarrow4}f(x)=4 \\ \lim _{x\rightarrow0^-}f(x)=-\infty \\ \lim _{x\rightarrow\infty}f(x)=\infty \\ \lim _{x\rightarrow0^+}f(x)=0 \end{gathered}[/tex]e. Yes, there are two possible values of x for the limit of the function approaching 4:
• x = 2,
,• x = 4.
By definition, a function is continuous when its graph is a single unbroken curve.
We see that at the points x = 2 and x = 4 the curve is a single unbroken curve, so we conclude that the function is continuous at those points.
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