At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

7x + 3y = 5 find the slope and y intercept and make a new equation find if there’s one solution no solution or an infinite number of solutions 4x + 3y =6 the slope and y intercept and make a new equation find if there’s one solution no solution or an infinite number of solutions

7x 3y 5 Find The Slope And Y Intercept And Make A New Equation Find If Theres One Solution No Solution Or An Infinite Number Of Solutions 4x 3y 6 The Slope And class=

Sagot :

Hello there. To solve this question, we'll have to remember some properties about system of linear equations and how to find the equation of a line in slope-intercept form.

Given the equation of a line

[tex]ax+dy=c[/tex]

We can solve for y in order to find it in slope-intercept form

[tex]y=mx+b[/tex]

Where m is the slope and b is the y-intercept.

For the first equation, we get

[tex]7x+3y=5[/tex]

Solving for y, we first subtract 7x on both sides of the equation

[tex]3y=-7x+5_{}[/tex]

Divide both sides of the equation by a factor of 3

[tex]y=-\frac{7}{3}x+\frac{5}{3}[/tex]

And we can spot the slope as m = -7/3 and the y-intercept = 5/3.

For the second equation, we have

[tex]4x+3y=6[/tex]

Solving for y, subtract 4x on both sides of the equation

[tex]3y=-4x+6[/tex]

Divide both sides by a factor of 6

[tex]y=-\frac{4}{3}x+2[/tex]

The slope in this case is equal to -4/3 and the y-intercept is equal to 2.

Finally, to determine if the system has one, infinite or no solutions, we make:

[tex]\begin{cases}7x+3y=5 \\ 4x+3y=6\end{cases}[/tex]

The first way to make sure is that if we can find a single ordered pair (x, y) that satisfies this system. Subtract the second equation from the first, such that

[tex]\begin{gathered} 7x+3y-(4x+3y)=5-6 \\ 7x+3y-4x-3y=-1 \\ 3x=-1 \end{gathered}[/tex]

Divide both sides by a factor of 3

[tex]x=-\frac{1}{3}[/tex]

Plugging this into any equation, we find the solution for y

[tex]\begin{gathered} 4\cdot\mleft(-\dfrac{1}{3}\mright)+3y=6 \\ -\frac{4}{3}+3y=6 \\ 3y=6+\frac{4}{3}=\frac{22}{3} \\ y=\frac{22}{9} \end{gathered}[/tex]

Hence the ordered pair that is a solution of this system of equations is

[tex]\mleft(-\dfrac{1}{3},\frac{22}{9}\mright)[/tex]

This is in fact the unique solution to this system, since the lines only cross this time at x = -1/3 and y = 22/9.

The other way to check is if the determinant of the coefficients matrix is different of zero:

[tex]\begin{bmatrix}{7} & {3} \\ {4} & {3}\end{bmatrix}[/tex]

Taking this determinant, that is, subtracting the products between the main and secondary diagonals, we have

[tex]7\cdot3-4\cdot3=21-12=9[/tex]

That means that this system has only one solution.

For a system of linear equations (in fact, two lines)