In order to find the total displacement of a 8 meters north vector and a 8 meters east vector, we first need to know that these vectors forms a right angle (because the north and east directions forms a 90° angle).
So, to find the final displacement, we need to sum these vectors, and this sum can be calculated using the Pythagoras' theorem in the resultant triangle:
[tex]\begin{gathered} d^2=8^2+8^2 \\ d^2=64+64 \\ d^2=128 \\ d=\sqrt{128=8\sqrt{2=}}11.31 \end{gathered}[/tex]
So the total displacement is 11.31 meters.
