We will analyze this triangle, as we can see we have a right triangle so we can use the trigonometric functions
[tex]\begin{gathered} \tan (45)=\frac{24}{w} \\ w=\frac{24}{\tan (45)} \\ w=24 \end{gathered}[/tex][tex]\begin{gathered} \cos (45)=\frac{24}{x} \\ x=\frac{24}{\cos (45)}= \\ x=24\sqrt[]{2} \end{gathered}[/tex]
Then we have
[tex]\begin{gathered} \tan (60)=\frac{24}{y} \\ y=\frac{24}{\tan60}=8\sqrt[]{3} \end{gathered}[/tex]
[tex]\begin{gathered} \sin (60)=\frac{24}{z} \\ z=\frac{24}{\sin (60)} \\ z=16\sqrt[]{3} \end{gathered}[/tex]
