Answered

Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Anthony has two bags of marbles. the first bag contains 12 red marbles, and 8 green marbles. The second bad contains 6 red marbles, 4 blue marbles, and 8 green marbles. Anthony will randomly select 1 marble from each bag. What is the probability that he will select a red marble from each bag

Sagot :

First bag:

Red = 12

Green = 8

Second bag:

Red = 6

Blue = 4

Green = 8

The probability to select a red marble from each bag can be calculated using:

[tex]P(\text{Red})=\frac{\text{ Number of reds}}{\text{ Total}}[/tex]

Now, for the first bag:

[tex]P_1(\text{Red})=\frac{12}{20}=\frac{3}{5}[/tex]

Now, for the second bag:

[tex]P_2(\text{Red})=\frac{6}{18}=\frac{1}{3}[/tex]

Both selections are independent events, so the overall probability to select a red marble from each bag is just the product of P₁ and P₂:

[tex]\begin{gathered} P(\text{Red})=P_1(\text{Red})\cdot P_2(\text{Red})=\frac{3}{5}\cdot\frac{1}{3} \\ P(\text{Red})=\frac{1}{5} \end{gathered}[/tex]

We hope this was helpful. Please come back whenever you need more information or answers to your queries. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.