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Sagot :
The general slope-intercept form is:
y = ax + b
where a is the slope and b is the y-intercept.
The value of b represents the initial value of y, i.e., when x = 0. So for this problem, we have:
b = 13980
since this was the value of y (average value of the automobile) when x = 0 (the year 1995).
Until now, we obtained the equation:
y = ax + 13980
Now, in order to find a, we can use the fact that, for x = 4 (1999 - 1995 = 4), y = 7860:
7860 = a(4) + 13980
Then, we need to isolate the constant a at one side of the equation and find its value:
7860 = a(4) + 13980
7860 = 4a + 13980
7860 - 13980 = 4a
-6120 = 4a
-6120/4 = a
a = -1530
Therefore, the linear equation is:
y = -1530x + 13980
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