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What volume of each solution contains 0.275 mol of NaI? Soltion 1) 0.902 M NaISolution 2) 1.61 M NaI

Sagot :

Molarity is given by the following equation:

[tex]M=\frac{mol}{liters}[/tex]

From this equation, we can solve for liters and use the given values:

[tex]liters=\frac{mol}{M}[/tex]

Replace for the given values:

1. 0.902M

[tex]liters=\frac{0.275mol}{0.902M}=0.305lt[/tex]

2. 1.61M

[tex]liters=\frac{0.275mol}{1.61M}=0.171lt[/tex]

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