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Sagot :
ABCD is a parallelogram
diagonals AB bisect BD at E
In triangle AED and CEB, DAE = BCE (alternate interior angles)
AD = CB
ADE = CBE (alternate interior angles)
AED CEB (ASA)
Hence, AE = CE and ED = EB
Thus, the diagonals of a parallelogram bisect each other.
Hence, segment AE is congruent to segment CE
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