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what is the approximate diameter a sphere with a volume of 268 cm ^3

Sagot :

By formula,

[tex]V=\frac{4\pi r^3}{3}[/tex]

Cross multiply, we get,

[tex]\begin{gathered} 4\pi r^3=3V \\ r^3=\text{ }\frac{3V}{4\pi}=\frac{3(268)(7)}{4(22)}=63.955 \\ \\ r=\sqrt[3]{63.955} \\ r=3.999\approx4\operatorname{cm} \end{gathered}[/tex]

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