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I need help I don’t understand this question. DC=8.5, DW=6.

I Need Help I Dont Understand This Question DC85 DW6 class=

Sagot :

Recall that the diagonals of a square bisect each other, therefore:

[tex]BW=DW=6.[/tex]

The diagonals are congruent, therefore:

[tex]AC\cong DB=2DW=2(6)=12.[/tex]

To compute DA we use the fact that the figure is a square:

[tex]DA=DC=8.5.[/tex]

Now, we know that the angles at the vertices are right angles, therefore:

[tex]m\angle ABC=90.[/tex]

To determine the measure of angles ABD, and DCA we use the trigonometric function sine:

[tex]\begin{gathered} sin(\angle ABD)=\frac{DA}{DB}=\frac{\sqrt{287}}{2(12)}, \\ sin(\angle DCA)=\frac{DA}{CA}=\frac{\sqrt{287}}{2(12)}. \end{gathered}[/tex]

Therefore:

[tex]m\angle ABD=m\angle DCA\approx45^{\circ}.[/tex]

Finally, to determine the measure of angle DWA, we use the fact that the figure is a square, therefore the diagonals bisect each other at 90° angles.

Answer:

[tex]\begin{gathered} BW=6, \\ AC=12, \\ DA=8.5, \\ m\angle DWA=90^{\circ}, \\ m\angle ABC=90^{\circ}, \\ m\angle ABD=45^{\circ}, \\ m\angle DCA=45^{\circ}. \end{gathered}[/tex]

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