Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
In order to find the direction of the initial velocity, first let's calculate the change in velocity caused by the acceleration:
[tex]\begin{gathered} F=m\cdot a\\ \\ 2655=15.5\cdot a\\ \\ a=171.29\text{ m/s^^b2}\\ \\ \\ \\ \Delta V=a\cdot t\\ \\ \Delta V=171.29\cdot0.05\\ \\ \Delta V=8.5645\text{ m/s} \end{gathered}[/tex]Now, let's calculate the horizontal and vertical components of the final velocity.
The direction is N45W, therefore the angle is 90° + 45° = 135°:
[tex]\begin{gathered} V_x=V\cdot\cos135°=45\cdot(-\frac{\sqrt{2}}{2})=-31.82\text{ m/s}\\ \\ V_y=V\cdot\sin135°=45\cdot\frac{\sqrt{2}}{2}=31.82\text{ m/s} \end{gathered}[/tex]The change in the velocity occurred in north direction, so let's calculate the initial vertical velocity:
[tex]V_{iy}=V_y-\Delta V=31.82-8.5645=23.2555\text{ m/s}[/tex]Now, to calculate the direction, we can use the arc tangent below:
[tex]\theta=\tan^{-1}(\frac{V_{iy}}{V_{ix}})=\tan^{-1}(\frac{23.2555}{-31.82})=-36.16°[/tex]Since the direction is between north and west, we need to add 180° to the result, so the angle will be 143.84°.
This angle is equal to the direction N 53.84° W.
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
