the slope -intercept form of the equation of a line is
[tex]\begin{gathered} y=mx+b \\ where\text{ m is the slope} \\ b\text{ is the y-intercept} \end{gathered}[/tex]so
Step 1
find the slope of the line:
2 lines that are parellel has the same slope , so the slope of the line we are looking for must equal to the slope of
[tex]\begin{gathered} y=6x+7 \\ y=6x+7\Rightarrow y=mx+b \\ so \\ m=slope=6 \end{gathered}[/tex]so
slope=6
Step 2
now, we need to use the point-slope formula , it says
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ where \\ m\text{ is the slope and } \\ P1(x_1,y_1)\text{ is a well known of the line} \end{gathered}[/tex]so
a) let
[tex]\begin{gathered} slope=6 \\ P1(8,-9) \end{gathered}[/tex]b) now, replace and solve for y
[tex]\begin{gathered} y-y_{1}=m(x-x_{1}) \\ y-(-9)=6(x-8) \\ y+9=6x-48 \\ subtract\text{ 9 in both sides} \\ y+9-9=6x-48-9 \\ y=6x-57 \end{gathered}[/tex]therefore, the answer is
[tex]y=6x-57[/tex]I hope this helps you