Answered

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[tex] \frac{x}{3} - 3 = \frac{x}{9} + 3[/tex]what value of c make this equation true?

Sagot :

The given expression:

[tex]\frac{x}{3}-3=\frac{x}{9}+3[/tex]

Arrange the variables terms and constant term together:

[tex]\begin{gathered} \frac{x}{3}-3=\frac{x}{9}+3 \\ \frac{x}{3}-\frac{x}{9}=3+3 \end{gathered}[/tex]

Least Common multiple of 3 & 9 is 9

[tex]\begin{gathered} \frac{x}{3}-\frac{x}{9}=3+3 \\ \frac{3x-x}{9}=6 \\ \frac{2x}{9}=6 \end{gathered}[/tex]

Apply cross multiplication:

[tex]\begin{gathered} \frac{2x}{9}=6 \\ 2x=6\times9 \\ x=\frac{6\times9}{2} \\ x=27 \end{gathered}[/tex]

Answer: J) 27

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