Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Given data
*The given mass of the car is m = 885 kg
*The given speed is u = 40 m/s
*The given acceleration of the car is a = 3 m/s^2
*The given distance is s = 200 m
*The height of the cliff is H = 120 m
(a)
The formula for the time taken by the car is given by the equation of motion as
[tex]s=ut+\frac{1}{2}at^2[/tex]Substitute the values in the above expression as
[tex]\begin{gathered} 200=(40)t+\frac{1}{2}\times3\times t^2 \\ 200=40t+1.5t^2 \\ t=4.30\text{ s} \end{gathered}[/tex]Hence, the time taken by the car is t = 4.30 s
(b)
The formula for the time taken by the car to land is given as
[tex]T=\sqrt[]{\frac{2H}{g}}[/tex]*Here g is the acceleration due to the gravity
Substitute the values in the above expression as
[tex]\begin{gathered} T=\sqrt[]{\frac{2\times120}{9.8}} \\ =4.94\text{ s} \end{gathered}[/tex]Hence, the time taken by the car to land is T = 4.94 s
(c)
The formula for the horizontal distance from the cliff is given as
[tex]R=u\times T[/tex]Substitute the values in the above expression as
[tex]\begin{gathered} R=(40)(4.94) \\ =197.6\text{ m} \end{gathered}[/tex]Hence, the horizontal distance from the cliff is R = 197.6 m
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.