Answered

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2. *The lines 2x + 3y = 6 and 4x – ky = 10 are parallel. Find the value of k.0

Sagot :

k = -6

Explanation:

The first equation: 2x + 3y = 6

The second equation: 4x – ky = 10

For two lines to be parallel to each other, the slope of both lines must be equal.

2x + 3y = 6

Rewritting in the slope-intercept form to get the slope:

3y = -2x + 6

y = -2x/3 + 6/3

y = -2x/3 + 2

4x – ky = 10

Rewritting in the slope-intercept form to get the slope:

ky = 4x - 10

y = 4x/k - 10

Equating both slope since they are equal:

-2x/3 = 4x/k

cross multiply:

-2xk = 12x

divide both sides by x:

-2k = 12

k = 12/-2

k = -6

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