Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
SOLUTION
Step 1 :
Given
[tex]\begin{gathered} f(x)=x^2\text{ + x } \\ \text{g ( x ) =x }^2 \end{gathered}[/tex][tex]\begin{gathered} 1.(f+g)(x)=x^2+x+x^2=2x^2\text{ + x} \\ (f+g)(x)=2x^2\text{ + x } \end{gathered}[/tex][tex]\begin{gathered} 2.\text{ Domain of ( f + g ) ( x ) = ( -}\infty\text{ , }\infty\text{ )} \\ \end{gathered}[/tex][tex]\begin{gathered} 3.(f-g)(x)=x^2+x-x^2\text{ = x} \\ (\text{ f - g ) (x) = x } \end{gathered}[/tex][tex]4.\text{ Domain of ( f - g ) ( x ) = (- }\infty\text{ , }\infty\text{ )}[/tex][tex]5.fg(x)=(x^2+x)x^2=x^{\text{4 }}+x^3[/tex][tex]6.\text{ Domain of fg ( x ) = ( - }\infty\text{ , }\infty\text{ )}[/tex][tex]7.\text{ (}\frac{f}{g}\text{ )x = }\frac{x^2\text{ + x}}{x^2}\text{ = 1 + }\frac{1}{x}[/tex]
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.