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сa = 2 inb = 2 inWhat is the length of the hypotenuse?c =inches

Sagot :

Let's begin by listing out the given information:

[tex]\begin{gathered} a=2in,b=2in,c=\text{?} \\ \text{Pythagora}s\text{ Theorem states that:} \\ c^2=a^2+b^2 \\ c^2=2^2+2^2 \\ c^2=4+4=8 \\ c=\sqrt[]{8}=2\sqrt[]{2} \\ c=2\sqrt[]{2}in \end{gathered}[/tex]

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