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A line with a slope of 0 passes through the point (-15, 12). What is its equation in slope-intercept form?

Sagot :

We have to find the equation of a line in the slope-intercept form. We remember that it is given by:

[tex]y=mx+b[/tex]

where m represents the slope, and b the y-intercept.

In this exercise, we are given the slope:

[tex]m=0[/tex]

And that it passes through the point (-15,12). Replacing the slope onto the general form, and using the point, we get:

[tex]\begin{gathered} 12=0(-15)+b \\ 12=0+b \\ 12=b \end{gathered}[/tex]

And thus, its y-intercept is 12. This means that the equation in the slope-form is given by:

[tex]\begin{gathered} y=0x+12 \\ y=12 \end{gathered}[/tex]

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