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Sagot :
Explanation
We are asked to get the probability of rolling either a 2 or 6 in a single dice
To do so, we will make use of the probability definition:
Probability simply means the ratio of possible outcomes to the total number of outcomes
In our case
we have a dice, so the total outcome will be {1,2,3,4,5,6}
to roll a 2, the possible outcome is {2}
to roll a 6, the possible outcome is {6}
Thus, the probability of rolling a 2 will be
[tex]\frac{1}{6}[/tex]The probability of rolling a 6 will be
[tex]\frac{1}{6}[/tex]Therefore, the probability of rolling a 2 or 6
[tex]\begin{gathered} P=\frac{1}{6}+\frac{1}{6} \\ \\ P=\frac{1+1}{6}=\frac{2}{6}=\frac{1}{3} \end{gathered}[/tex]In per cent, we will have
[tex]\frac{1}{3}\times100=33.33\text{ \%}[/tex]To the nearest whole number, we will have 33%
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