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Sagot :
Activity 1:
We are given two triangles. The two side lengths of one triangle are known but of the other are not. Our task is to choose the value of x and y that will make the triangles congruent.
Now, the side lengths that are congruent are with 31 in the rightmost triangle and 7x -4 in the left-most triangle; therefore, equating them gives
[tex]7x-4=31[/tex]Similarly, side length 24 must equal 4y+8; therefore,
[tex]4y+8=24[/tex]Now we have to choose the values of x and y that will make both equations true.
Let us solve for x in the first equation by first adding 4 to both sides. Doing this gives
[tex]7x=35[/tex]Finally, dividing both sides by 7 gives
[tex]x=5.[/tex]Activity 2:
Now, for the value of y.
To solve for y, we first subtract 8 from both sides to get
[tex]4y=16[/tex]Finally, dividing both sides by 4 gives
[tex]y=4.[/tex]Hence, to conclude x = 5 and y = 4.
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