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If cos O 4/7 and csc O<0 , find sin Oand tan O

If Cos O 47 And Csc Olt0 Find Sin Oand Tan O class=

Sagot :

Explanation:

If cosθ = 4/7, we can represent it with the following triangle

To find the sinθ, we need to calculate the missing side x. Using the Pythagorean theorem, we get that the value of x is

[tex]\begin{gathered} x=\sqrt{7^2-4^2} \\ x=\sqrt{49-16} \\ x=\sqrt{33} \end{gathered}[/tex]

Then, sinθ and cscθ have the same sign, so sinθ will be negative and is equal to

[tex]\begin{gathered} \sin\theta=\frac{Opposite}{Hypotenuse} \\ \\ \sin\theta=\frac{x}{7} \\ \\ \sin\theta=-\frac{\sqrt{33}}{7} \end{gathered}[/tex]

Finally, tanθ is equal to

[tex]\begin{gathered} \tan\theta=\frac{Opposite}{Adjacent} \\ \\ \tan\theta=\frac{-\sqrt{33}}{4} \end{gathered}[/tex]

Answer:

Therefore, the answer is

[tex]\sin\theta=\frac{-\sqrt{33}}{7},\tan\theta=\frac{-\sqrt{33}}{4}[/tex]

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