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I am looking for help with slope-intercept form and liner model. Please see the attached question. Thank you

I Am Looking For Help With Slopeintercept Form And Liner Model Please See The Attached Question Thank You class=

Sagot :

Solution:

Given the scatter plot below:

A) To determine the equation of the line, we have

This implies that the line passes through the points (3, 10) and ((7, 7).

Thus, we have the equation to be evaluated as

[tex]\begin{gathered} y-10=(\frac{7-10}{7-3})(x-3) \\ \Rightarrow y-10=-\frac{3}{4}(x-3) \\ thus,\text{ } \\ y=-\frac{3}{4}(x-3)+10 \\ open\text{ parentheses,} \\ y=-\frac{3}{4}x+\frac{9}{4}+10 \\ \Rightarrow y=-\frac{3}{4}x+\frac{49}{4} \end{gathered}[/tex]

Thus, the equation of the line, in slope-intercept form, is

[tex]\begin{equation*} y=-\frac{3}{4}x+\frac{49}{4} \end{equation*}[/tex]

B) Based on the linear model, the number of hours Jerry worked on the day of the picnic, day 0, is

[tex]\begin{gathered} y=-\frac{3}{4}x+\frac{49}{4} \\ where \\ x=0, \\ y=-\frac{3}{4}(0)+\frac{49}{4} \\ \Rightarrow y=12.25\text{ hours} \end{gathered}[/tex]

Thus, Jerry worked 12.25 hours.

From the linear model, Jerry's setup time decreases by

[tex]0.75[/tex]

View image LeanE458192
View image LeanE458192