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A rectangular yard has a width to length ratio of 2:5. If the distance around the yard is 1400 feet, what are the dimensions of the yard?the yard is ______ ft wide and ______ ft long.

Sagot :

Answer:

length = 500 ft

width= 200 ft

Explanation:

Let us call w the width and L the length of the yard - then we know that

[tex]\frac{w}{L}=\frac{2}{5}[/tex]

in other words, the length to width ratio is 2 : 5.

Moreover, we also know that the distance around the yard (its perimeter) is 1400 ft - meaning

[tex]2(w+L)=1400[/tex]

Hence, we have two equations and two unknowns.

Now for solve for w in the first equation to get

[tex]w=\frac{2}{5}L[/tex]

substituting this value of w in the second equation gives

[tex]\begin{gathered} 2(w+L)=1400 \\ 2(\frac{2}{5}L+L)=1400 \end{gathered}[/tex]

the left-hand side simplifies to give

[tex]2(\frac{7}{5}L)=1400[/tex]

dividing both sides by 2 gives

[tex](\frac{7}{5}L)=\frac{1400}{2}[/tex][tex]\rightarrow(\frac{7}{5}L)=700[/tex]

Multiplying both sides by 5/7 gives

[tex]\frac{5}{7}\cdot(\frac{7}{5}L)=700\cdot\frac{5}{7}[/tex][tex]L=700\cdot\frac{5}{7}[/tex][tex]L=\frac{700\cdot5}{7}[/tex][tex]\boxed{L=500}[/tex]

Hence, the length of the yard is 500 ft.

With the value of length in hand, we now find the width using

[tex]w=\frac{2}{5}L[/tex]

since L = 500, the above equation becomes

[tex]w=\frac{2}{5}\cdot500[/tex][tex]w=\frac{2\cdot500}{5}[/tex][tex]\boxed{w=200}[/tex]

The width of the yard is 200 ft.

Hence, to summarize

The yard is 200 ft wide and 500 ft long.