Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Building 1(-5,-3) Building 2 is at (- 5, 5) Building 3 is at (4, 5) Building 4 is at (4, - 3) A bike courier begins at building 1 and then delivers packages to building 2 and then building 3, and then building 4. Then she bikes back to building 1. The path between each building is a straight line. One unit on the coordinate grid equals 100 feet What is the total distance the courier biked?

Sagot :

We have to use the distace between points formula to calculate the distance on each case.

Case 1: From Building 1 (-5,-3) to building 2 (-5,5)

[tex]d=\sqrt[]{(x2-x1)^2+(y2-y1)^2}[/tex][tex]d=\sqrt[]{(-5-(-5))^2+(5-(-3)^2}\text{ = 8}[/tex]

Case 2: From Building 2 (-5,5) to building 3 (4, 5)

[tex]d=\sqrt[]{(5-5)^2+(4-(-5))^2}\text{ = }9[/tex]

Case 3: From Building 3 (4, 5) to building 4 (4, - 3)

[tex]d=\sqrt[]{(-3-5)^2+(4-4)^2}\text{ = }8[/tex]

Case 4: From Building 4 (4, - 3) to building 1 (-5,-3)

[tex]d=\sqrt[]{(-3-(-3))^2+(-5-4)^2}\text{ = }9[/tex]

The sum of the distances is: 8+9+8+9= 34. And since one unit equals 100 feet. Then the distance biked is 3400 feet.

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.