Answered

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A set of 50 numbers consists of nine 7s, ten 8s, twelve 9s, ten 10s, five 11s, and the remainder were 12s. Find the mean of the numbers.

Sagot :

Given:

The total number is 50.

A set of 50 numbers consists of nine 7s, ten 8s, twelve 9s, ten 10s, five 11s, and the remainder were 12s.

Required:

To find the mean.

Explanation:

Here nine 7s, ten 8s, twelve 9s, ten 10s, five 11s, and the remainder were 12s.

So the remaining number is

[tex]\begin{gathered} =50-(9+10+12+5) \\ =50-36 \\ =14 \end{gathered}[/tex]

Now the mean is

[tex]\begin{gathered} =\frac{9\times7+10\times8+12\times9+5\times11+14\times12}{50} \\ \\ =\frac{63+80+108+55+168}{50} \\ \\ =\frac{474}{50} \\ \\ =9.48 \end{gathered}[/tex]

Final Answer:

The mean is 9.48

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