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On april 8th, a flower at blooming acres florist was 15. 0 centimeters tall. On april 16th, the flower was 17. 4 centimeters tall. If the flower grew at a constant rate, on what day was the flower 16. 5 centimeters tall?.

Sagot :

On calculating the rate of change, it can be obtained that

Date on which the flower was 16.5 cm tall = 13 April

What is rate of change?

Suppose there are two quantities. On changing the value of one quantity, the rate at which the other quantity changes is called rate of change.

Here,

On April 8th, a flower at blooming acres florist was 15. 0 centimeters tall.  On April 16th, the flower was 17. 4 centimeters tall.

Rate of change =

                            [tex]\frac{17.4 - 15}{16 - 8}\\\frac{2.4}{8}\\[/tex]

                            0.3 cm/day

Difference between 16.5 cm and 15 cm = 16.5 - 15  = 1.5 cm

Number of days required to grow from 15 cm to 16.5 cm = [tex]\frac{1.5}{0.3} =5[/tex] days

Date on which the flower was 16.5 cm tall = 8th April + 5 = 13 April

To learn more about rate of change, refer to the link-

https://brainly.com/question/11859175

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