Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

a pipe of length 6.0 m is closed at one end and sustains a standing wave at its second overtone. determine the distance between a node and an adjacent antinode.

Sagot :

The distance between a node and an adjacent antinode is 1.2m.

If λ is the wavelength then the length of the pipe L = 5λ/4

Now F₁ = ν/4L

        F₃ = 5F₁ for second overtone for system of two different ends,

so, wavelength λ = [tex]\frac{4L}{5}[/tex] = 4 × [tex]\frac{6}{5}[/tex] = 4.8m

the distance between a node and adjacent antinode = λ/4 = [tex]\frac{4.8}{4}[/tex] = 1.2m

In physics, what do node and antinode mean?

The location of a point on a standing wave is described by its node and antinodes. The points known as nodes are those that do not deviate from the equilibrium position. At nodes, amplitude is at its lowest. Antinodes are locations where deviations from the mean position are at their highest (at crests and toughs). Antinodes have the highest amplitude.

On the other side, antinodes are created in regions where constructive interference takes place. For instance, a point of significant positive displacement happens when the crests of two waves collide.

To know more about node and antinode visit:

https://brainly.com/question/6999573

#SPJ4