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consider the triangle formed by the side of the house, the ladder, and the ground. find the rate at which the area of the triangle is changing when the base of the ladder is 7 feet from the wall?

Sagot :

The rate at which the area of the triangle is changing when the base of the ladder is 7 feet from the wall is [tex]\frac{527}{24}ft^2/sec[/tex].

What is triangle?

Three edges and three vertices make up a triangle, which is a polygon. It is among the fundamental shapes in geometry. Triangle ABC refers to a triangle with the vertices A, B, and C. In Euclidean geometry, any three points that are not collinear determine a singular triangle and a singular plane at the same time.

Given:

dx / dt = 2 feet / sec

We have to find dA/dt when x = 7.

Since,

Area = 1/2 x (xy)

A = 1/2 x (xy)

Differentiating both sides with respect to t

[tex]\frac{dA}{dt} = \frac{1}{2}(\frac{dx}{dt}y+\frac{dy}{dt}x)\\[/tex]                 ..(1)

We have,

x^2 + y^2 = 25^2

plug x = 7

⇒ y = √(25^2 - 7^2)

y = √(625 - 49)

y = √576

y = 24

Now plug x = 7, y = 24, dx/dt = 2 and dy/dt = -7/12 in equation (1)

[tex]\frac{dA}{dt} = \frac{1}{2} (2(24) + (-\frac{7}{12})(7)) \\ \frac{dA}{dt} = \frac{527}{24} ft^2/sec[/tex]

Hence, the rate at which the area of the triangle is changing when the base of the ladder is 7 feet from the wall is [tex]\frac{527}{24}ft^2/sec[/tex].

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