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When a student is applying a rightward force of 6.5 N to a 1.80 kg box the box remains at rest. When the student applies a slightly larger force, the box moves to the right. Find the coefficient of static friction.

Sagot :

The coefficient of static friction is equal to 0.368.

What is static friction?

Static Friction can be described as friction that is experienced when an object is placed on a surface. Kinetic friction can be described as friction due to the movement of an object on a surface. The coefficient of static friction is a scalar parameter and is represented as μs.

The coefficient of static friction can be calculated from the following expression as:

[tex]{\displaystyle \mu_s ={\frac{ F}{mg}[/tex]

Given, the force acting on the box = 6.5 N

The mass of the box, m = 1.80 Kg

The gravitational acceleration, g = 9.8m/s²

The coefficient of static fraction = 6.5/(1.80 ×9.8) = 0.368  

Learn more about static friction, here:

https://brainly.com/question/13000653

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