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Sagot :
The mean, variance and the standard deviation for the distance travelled by 10 students is computed as-
Mean = 3.12; standard deviation = 1.8232; variance = 3.324
Describe the term standard deviation?
- The term "standard deviation" (or "σ") applies to a measurement of the data's dispersion from the mean.
- A low standard deviation denotes that the data are grouped around the mean, whereas a large standard deviation implies that the data are more dispersed.
Total students n = 10 .
Given the information, 1, 5, 2, 3, 5, 4, 8, 1, 2, 2, 5, 1.5, and 0.8
To determine the mean, we must first add up all the information provided and divide it by the number of students.
X = 1.1 + 5.2 + 3.6 + 5.0 + 4.8 + 1.8 + 2.2 + 5.2 + 1.5 + 0.8
X = 31.2
Mean = X/n
Mean = 31.2/10
Mean = 3.12
Now the standard deviation is estimated as-
S = √∑x² - [(∑x)²/n] / (n-1)
Putting the values-
s = 1.8232
standard deviation = 1.8232
The variance is estimated by -
variance = S²
S² = 1.8232²
variance = 3.324
Thus, the mean, variance and the standard deviation for the distance travelled by 10 students is computed.
To know more about the standard deviation, here
https://brainly.com/question/475676
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The complete question is-
In a random sample, 10 students were asked to compute the distance they travel one way to school to the nearest tenth of a mile. Compute the sample mean, standard mean, standard deviation and variance of the data:1.1 5.2 3.6 5.0 4.8 1.8 2.2 5.2 1.5 0.8 Mean = ?, Variance = ?; Standard Deviation= ?
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