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a student pipetted exactly 50.00 ml of 0.1038 m hcl into a 250-ml erlenmeyer flask containing 0.3735 g of an antacid tablet. the solution was heated and boiled to remove any co2. approximately 25 ml of water and three drops of phenolphthalein indicator was added to the erlenmeyer flask containing the hcl and antacid tablet. a 50 ml buret was rinsed and filled with a 0.1017 m naoh solution. the initial volume of the buret was read and recorded as 2.30 ml. the naoh solution was carefully added to the antacid/hcl solution until a permanent very slight pink coloration was noticed. the buret was read again and recorded as 22.82 ml. calculate the acid equivalent (g hcl/g antacid) of the antacid tablet.

Sagot :

SuchandraC

The acid equivalent of the antacid tablet is 0.303 g HCl/ g antacid.

What is mole?

In chemistry, the term "mole" (sometimes written "mole") refers to a standard scientific unit for measuring vast amounts of extremely small objects like atoms, molecules, or other specific particles.

The mole represents 6.02214076 × 10²³ units, an astronomically huge number.

We have,

Total moles of HCl added = 0.1038 M × 50.0 mL × 1L/1000mL

= 0.00519 mol

Now, volume of NaOH used = 22.82mL - 2.30 mL

= 20.52 mL

Moles of NaOH used = 0.1017 M × 20.52 mL × 1L/1000mL

= 0.00209 mol

Moles of HCl that reacted with antacid = 0.00519 - 0.00209 mol

= 0.0031 mol

Total mass of HCl reacted = 0.0031 × 36.45g HCl / 1mol HCl

=0.113 g

Acid equivalent of antacid tablet = 0.113g HCl / 0.3735g antacid

= 0.303 g HCl/ g antacid.

To know more about moles, check out https://brainly.com/question/15356425

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