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What is the equation of the line that is parallel to the given line and passes through the given point?

A. [tex]\( y = -2 \)[/tex]
B. [tex]\( x = -2 \)[/tex]
C. [tex]\( y = -4 \)[/tex]
D. [tex]\( x = -4 \)[/tex]

Sagot :

To find the equation of a line that is parallel to [tex]\( y = -2 \)[/tex] and passes through the point [tex]\( (-4, -4) \)[/tex], follow these steps:

1. Understand the given line: The line [tex]\( y = -2 \)[/tex] is a horizontal line. Horizontal lines have the same [tex]\( y \)[/tex]-coordinate for all [tex]\( x \)[/tex]-values. Therefore, any line parallel to [tex]\( y = -2 \)[/tex] must also be a horizontal line.

2. Characteristic of parallel lines: Since horizontal lines are parallel if they have the same slope (which is zero for a horizontal line), the equation of any line parallel to [tex]\( y = -2 \)[/tex] will be in the form of [tex]\( y = c \)[/tex], where [tex]\( c \)[/tex] is a constant.

3. Determine the parallel line's constant [tex]\( c \)[/tex]: The parallel line must pass through the given point [tex]\( (-4, -4) \)[/tex]. For the line to pass through this point, the [tex]\( y \)[/tex]-coordinate of the line must equal [tex]\(-4\)[/tex].

Therefore, the equation of a horizontal line that passes through the point [tex]\( (-4, -4) \)[/tex] is:

[tex]\[ y = -4 \][/tex]

This means the equation of the line parallel to [tex]\( y = -2 \)[/tex] and passing through [tex]\( (-4, -4) \)[/tex] is:

[tex]\[ y = -4 \][/tex]