At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Question 3 of 10

In order to solve the following system of equations by addition, which of the following could you do before adding the equations so that one variable will be eliminated when you add them?

[tex]\[
\begin{array}{l}
2x - 4y = 5 \\
6x - 3y = 10
\end{array}
\][/tex]

Sagot :

To solve the given system of equations by the method of addition (also known as the elimination method), follow these steps to eliminate one of the variables. Let's consider the system of equations:

[tex]\[ \begin{array}{l} 2x - 4y = 5 \\ 6x - 3y = 10 \end{array} \][/tex]

## Step 1: Identify the coefficients of the variable to be eliminated

First, choose a variable to eliminate. For this solution, let’s choose to eliminate \( x \). To do this, we need the coefficients of \( x \) in both equations to be equal in magnitude.

## Step 2: Make the coefficients of \( x \) equal in magnitude

The coefficients of \(x\) in the given equations are \(2\) in the first equation and \(6\) in the second equation. To eliminate \( x \), we need to make these coefficients the same. We can do this by multiplying the first equation by 3:

[tex]\[ 3 \cdot (2x - 4y) = 3 \cdot 5 \][/tex]

This gives us:

[tex]\[ 6x - 12y = 15 \][/tex]

Now, the system of equations is:

[tex]\[ \begin{array}{l} 6x - 12y = 15 \\ 6x - 3y = 10 \end{array} \][/tex]

## Step 3: Make the coefficients opposites

Next, to eliminate \( x \), we want the coefficients to be opposite in sign. To do this, we can multiply the second equation by -2:

[tex]\[ -2 \cdot (6x - 3y) = -2 \cdot 10 \][/tex]

This gives us:

[tex]\[ -12x + 6y = -20 \][/tex]

Now our system of equations is:

[tex]\[ \begin{array}{l} 6x - 12y = 15 \\ -12x + 6y = -20 \end{array} \][/tex]

So, the system after making the coefficients of \( x \) equal in magnitude but opposite in sign is:

[tex]\[ \begin{array}{l} 6x - 12y = 15 \\ -12x + 6y = -20 \end{array} \][/tex]

Now, add these two equations to eliminate the variable \( x \).

## Step 4: Add the equations

[tex]\[ (6x - 12y) + (-12x + 6y) = 15 + (-20) \][/tex]

This simplifies to:

[tex]\[ -6x - 6y = -5 \][/tex]

In this form, one variable, \( x \), has been successfully eliminated, and we can now solve for \( y \).

Thus, before adding the equations, you should:
1. Multiply the first equation by 3.
2. Multiply the second equation by -2.

This step-by-step procedure ensures that one variable is eliminated when the equations are added.