At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
Sure, let's work through the polynomial division of [tex]\( \frac{x^3 - 1}{x - 1} \)[/tex].
To divide [tex]\( x^3 - 1 \)[/tex] by [tex]\( x - 1 \)[/tex], we can use polynomial long division. Here are the steps:
1. Set up the division: Write [tex]\( x^3 - 1 \)[/tex] as [tex]\( x^3 + 0x^2 + 0x - 1 \)[/tex] to account for all terms.
```plaintext
_______________
x - 1 | x^3 + 0x^2 + 0x - 1
```
2. Divide the leading term: Divide the leading term of the dividend [tex]\( x^3 \)[/tex] by the leading term of the divisor [tex]\( x \)[/tex]. This gives us [tex]\( x^2 \)[/tex].
```plaintext
x^2
_______________
x - 1 | x^3 + 0x^2 + 0x - 1
```
3. Multiply and subtract: Multiply [tex]\( x^2 \)[/tex] by the entire divisor [tex]\( x - 1 \)[/tex], and subtract this product from the original dividend.
```plaintext
x^2
_______________
x - 1 | x^3 + 0x^2 + 0x - 1
-(x^3 - x^2)
_______________
x^2 + 0x - 1
```
4. Bring down the next term: The result is [tex]\( x^2 + 0x - 1 \)[/tex].
5. Repeat the process: Now, divide the leading term [tex]\( x^2 \)[/tex] by [tex]\( x \)[/tex], which gives [tex]\( x \)[/tex]. Then multiply [tex]\( x \)[/tex] by [tex]\( x - 1 \)[/tex] and subtract again.
```plaintext
x^2 + x
_______________
x - 1 | x^3 + 0x^2 + 0x - 1
-(x^3 - x^2)
_______________
x^2 + 0x - 1
-(x^2 - x)
_______________
x - 1
```
6. Divide again: Divide the leading term [tex]\( x \)[/tex] by [tex]\( x \)[/tex], which gives 1. Multiply 1 by [tex]\( x - 1 \)[/tex] and subtract.
```plaintext
x^2 + x + 1
_______________
x - 1 | x^3 + 0x^2 + 0x - 1
-(x^3 - x^2)
_______________
x^2 + 0x - 1
-(x^2 - x)
_______________
x - 1
-(x - 1)
_______________
0
```
The remainder is 0, and the quotient is [tex]\( x^2 + x + 1 \)[/tex].
Therefore, the result of the polynomial division [tex]\( \frac{x^3 - 1}{x - 1} \)[/tex] is:
[tex]\[ x^2 + x + 1 \][/tex]
To divide [tex]\( x^3 - 1 \)[/tex] by [tex]\( x - 1 \)[/tex], we can use polynomial long division. Here are the steps:
1. Set up the division: Write [tex]\( x^3 - 1 \)[/tex] as [tex]\( x^3 + 0x^2 + 0x - 1 \)[/tex] to account for all terms.
```plaintext
_______________
x - 1 | x^3 + 0x^2 + 0x - 1
```
2. Divide the leading term: Divide the leading term of the dividend [tex]\( x^3 \)[/tex] by the leading term of the divisor [tex]\( x \)[/tex]. This gives us [tex]\( x^2 \)[/tex].
```plaintext
x^2
_______________
x - 1 | x^3 + 0x^2 + 0x - 1
```
3. Multiply and subtract: Multiply [tex]\( x^2 \)[/tex] by the entire divisor [tex]\( x - 1 \)[/tex], and subtract this product from the original dividend.
```plaintext
x^2
_______________
x - 1 | x^3 + 0x^2 + 0x - 1
-(x^3 - x^2)
_______________
x^2 + 0x - 1
```
4. Bring down the next term: The result is [tex]\( x^2 + 0x - 1 \)[/tex].
5. Repeat the process: Now, divide the leading term [tex]\( x^2 \)[/tex] by [tex]\( x \)[/tex], which gives [tex]\( x \)[/tex]. Then multiply [tex]\( x \)[/tex] by [tex]\( x - 1 \)[/tex] and subtract again.
```plaintext
x^2 + x
_______________
x - 1 | x^3 + 0x^2 + 0x - 1
-(x^3 - x^2)
_______________
x^2 + 0x - 1
-(x^2 - x)
_______________
x - 1
```
6. Divide again: Divide the leading term [tex]\( x \)[/tex] by [tex]\( x \)[/tex], which gives 1. Multiply 1 by [tex]\( x - 1 \)[/tex] and subtract.
```plaintext
x^2 + x + 1
_______________
x - 1 | x^3 + 0x^2 + 0x - 1
-(x^3 - x^2)
_______________
x^2 + 0x - 1
-(x^2 - x)
_______________
x - 1
-(x - 1)
_______________
0
```
The remainder is 0, and the quotient is [tex]\( x^2 + x + 1 \)[/tex].
Therefore, the result of the polynomial division [tex]\( \frac{x^3 - 1}{x - 1} \)[/tex] is:
[tex]\[ x^2 + x + 1 \][/tex]
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.