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Riley solved an equation, as shown in the table.

\begin{tabular}{|c|c|}
\hline Step & Statement \\
\hline 1 & [tex]$-2x + 4 = 3$[/tex] \\
\hline 2 & [tex]$-2x + 4 - 4 = 3 - 4$[/tex] \\
\hline 3 & [tex]$-2x = -1$[/tex] \\
\hline 4 & [tex]$\frac{-2x}{-2} = \frac{-1}{-2}$[/tex] \\
\hline 5 & [tex]$x = \frac{1}{2}$[/tex] \\
\hline
\end{tabular}

Which statement is true?

A. Riley made a mistake in step 2.

B. Riley made a mistake in step 4.

C. Riley made a mistake in step 5.

D. Riley solved the equation correctly.

Sagot :

Let's examine each step that Riley took while solving the equation.

Step 1:
[tex]\[ -2x + 4 = 3 \][/tex]

This is the starting equation.

Step 2:
[tex]\[ -2x + 4 - 4 = 3 - 4 \][/tex]

In this step, Riley is subtracting 4 from both sides of the equation to isolate the term with [tex]\( x \)[/tex]. Let’s simplify both sides:
[tex]\[ -2x + 4 - 4 = -2x \][/tex]
[tex]\[ 3 - 4 = -1 \][/tex]
So, the equation is simplified to:
[tex]\[ -2x = -1 \][/tex]

Step 3:
[tex]\[ -2x = -1 \][/tex]

This shows the result from Step 2.

Step 4:
[tex]\[ \frac{-2x}{2} = \frac{-1}{2} \][/tex]

Here, Riley is dividing both sides of the equation by -2 to solve for [tex]\( x \)[/tex]. Simplifying the left side:
[tex]\[ \frac{-2x}{2} = x \][/tex]
And the right side:
[tex]\[ \frac{-1}{2} = -\frac{1}{2} \][/tex]

So, we get:
[tex]\[ x = -\frac{1}{2} \][/tex]

Step 5:
[tex]\[ x = -\frac{1}{2} \][/tex]

This is the result from Step 4.

Now, let’s verify the steps:

The simplification in Step 2 results in:
[tex]\[ -2x = -1 \][/tex]
which is correct.

Dividing both sides by -2 in Step 4 results in:
[tex]\[ x = -\frac{1}{2} \][/tex]
which is also correct.

Thus, the final solution matches the steps preceding it correctly.

Therefore, the true statement is:
Riley solved the equation correctly.
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