To solve the problem of determining how much Charlie can spend on each sandwich, let's break down the situation step by step.
1. Identify the Given Values:
- Charlie wants to buy 6 sandwiches.
- He also needs to buy a [tex]$2 kid's meal.
- He has a total budget of $[/tex]32.
2. Set Up the Inequality:
- Let [tex]\( x \)[/tex] be the cost of each sandwich.
- So, the total cost for the sandwiches would be [tex]\( 6x \)[/tex].
- The total cost for both the sandwiches and the kid's meal is [tex]\( 6x + 2 \)[/tex].
- This total expenditure must be less than or equal to Charlie's budget of [tex]$32.
- Hence, the inequality can be written as:
\[
6x + 2 \leq 32
\]
3. Solve the Inequality for \( x \):
- Subtract 2 from both sides:
\[
6x + 2 - 2 \leq 32 - 2
\]
\[
6x \leq 30
\]
- Divide both sides by 6:
\[
\frac{6x}{6} \leq \frac{30}{6}
\]
\[
x \leq 5
\]
4. Interpret the Solution:
- The maximum amount Charlie can spend on each sandwich is $[/tex]5.
- Therefore, the correct answers are:
[tex]\[
\textbf{C. Inequality: } 6x + 2 \leq 32
\][/tex]
[tex]\[
\textbf{F. Answer: } \$ 5 \text{ or less}
\][/tex]
So, the correct choices that represent the inequality and the answer are:
C and F.
