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Sagot :
To solve for [tex]\( c \)[/tex] in the equation [tex]\( 5c - 2 = 3c \)[/tex], follow these steps:
1. Isolate the variable [tex]\( c \)[/tex]:
[tex]\[ 5c - 2 = 3c \][/tex]
2. Subtract [tex]\( 3c \)[/tex] from both sides:
[tex]\[ 5c - 3c - 2 = 3c - 3c \][/tex]
This simplifies to:
[tex]\[ 2c - 2 = 0 \][/tex]
3. Add 2 to both sides to isolate the term with [tex]\( c \)[/tex]:
[tex]\[ 2c - 2 + 2 = 0 + 2 \][/tex]
Thus, we get:
[tex]\[ 2c = 2 \][/tex]
4. Divide both sides by 2 to solve for [tex]\( c \)[/tex]:
[tex]\[ \frac{2c}{2} = \frac{2}{2} \][/tex]
Which simplifies to:
[tex]\[ c = 1 \][/tex]
Now, to find [tex]\( 24c \)[/tex]:
5. Substitute [tex]\( c = 1 \)[/tex] into [tex]\( 24c \)[/tex]:
[tex]\[ 24 \cdot 1 = 24 \][/tex]
Therefore, [tex]\( 24c = 24 \)[/tex].
The correct answer is:
[tex]\[ \boxed{24} \][/tex]
1. Isolate the variable [tex]\( c \)[/tex]:
[tex]\[ 5c - 2 = 3c \][/tex]
2. Subtract [tex]\( 3c \)[/tex] from both sides:
[tex]\[ 5c - 3c - 2 = 3c - 3c \][/tex]
This simplifies to:
[tex]\[ 2c - 2 = 0 \][/tex]
3. Add 2 to both sides to isolate the term with [tex]\( c \)[/tex]:
[tex]\[ 2c - 2 + 2 = 0 + 2 \][/tex]
Thus, we get:
[tex]\[ 2c = 2 \][/tex]
4. Divide both sides by 2 to solve for [tex]\( c \)[/tex]:
[tex]\[ \frac{2c}{2} = \frac{2}{2} \][/tex]
Which simplifies to:
[tex]\[ c = 1 \][/tex]
Now, to find [tex]\( 24c \)[/tex]:
5. Substitute [tex]\( c = 1 \)[/tex] into [tex]\( 24c \)[/tex]:
[tex]\[ 24 \cdot 1 = 24 \][/tex]
Therefore, [tex]\( 24c = 24 \)[/tex].
The correct answer is:
[tex]\[ \boxed{24} \][/tex]
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