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A plane leaves London where the tempretaure outside is 17 C.
The plane rises to a height where the tempreture outside is -43 C.
The tempreture decreases by 2 C with every increase of 300 m in height.
The maximum height of plane is

Sagot :

Answer:

First you find the difference in temperature. Final temperature minus initial temperature. -43-17=-60 So for every 300m temp will minus 2C.

There's a difference of -60, how many -2 is in -60? So -60÷(-2)= 30. 30 times 300m = 9000m or 9km.

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