Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Find the equation of the line described.
Perpendicular to y = 3x + 6; passing through the point (4,5).
The line equation is y =

Sagot :

Answer:

y = - [tex]\frac{1}{3}[/tex] x + [tex]\frac{19}{3}[/tex]

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x + 6 ← is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{3}[/tex] , thus

y = - [tex]\frac{1}{3}[/tex] x + c ← is the partial equation

To find c , substitute (4, 5) into the partial equation

5 = - [tex]\frac{4}{3}[/tex] + c ⇒ c = 5 + [tex]\frac{4}{3}[/tex] = [tex]\frac{19}{3}[/tex]

y = - [tex]\frac{1}{3}[/tex] x + [tex]\frac{19}{3}[/tex] ← equation of perpendicular line

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.